How to find the pairs of numbers from an array whose sum is divisible by 9

import java.util.ArrayList;
import java.util.List;

public class SumpairsDivby9 {

	public static List<Integer> divby9(int[] tempArr) {

		List<Integer> answerPairs=new ArrayList<Integer>();

		System.out.println("The hardcoded array of integers given below");
		System.out.print("[ ");
		for(int i=0;i<tempArr.length;i++)
			System.out.print(tempArr[i]+" ");
		System.out.println("]");
		//Traverse through the array using nested for loop, and check whether the sum of the successive numbers divisible by 9
		for (int i=0;i<tempArr.length;i++) {
			for(int j=i+1;j<tempArr.length;j++) {
				int sum = tempArr[i]+tempArr[j];
				if (sum%9==0) {
					answerPairs.add(tempArr[i]);
					answerPairs.add(tempArr[j]);			
				}		
			}
		}
		return answerPairs;
	}

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int[] intArr= {14,20,7,16,25,34,4};
		System.out.println("OUTPUT:");

		//Calling the function divby9 which computes the sum of pairs divisible by 9
		List<Integer> retPairs=divby9(intArr);

		System.out.println("The pairs of numbers which are divisible by 9");
		for(int i=0;i<retPairs.size();i+=2)
			System.out.println(retPairs.get(i)+"    "+retPairs.get(i+1));
	}
}