How to find the triplet numbers from an array whose sum is divisible by 9

import java.util.ArrayList;
import java.util.List;

public class SumtripletsDivby9 {

	public static List<Integer> divby9(int[] tempArr) {

		List<Integer> answerTriplets=new ArrayList<Integer>();

		System.out.println("The hardcoded array of integers given below");
		System.out.print("[ ");
		for(int i=0;i<tempArr.length;i++)
			System.out.print(tempArr[i]+" ");
		System.out.println("]");
		//Traverse through the array using nested for loop, and check whether the sum of the any three successive numbers divisible by 9
		for (int i=0;i<tempArr.length;i++) {
			for(int j=i+1;j<tempArr.length;j++) {
				for(int k=j+1;k<tempArr.length;k++) {
					int sum = tempArr[i]+tempArr[j]+tempArr[k];
					if (sum%9==0) {
						answerTriplets.add(tempArr[i]);
						answerTriplets.add(tempArr[j]);			
						answerTriplets.add(tempArr[k]);
					}		
				}	
			}
		}
		return answerTriplets;
	}

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int[] intArr= {14,20,11,5,29,17,58};
		System.out.println("OUTPUT:");

		//Calling the function divby9 which computes the sum of triplets divisible by 9
		List<Integer> retTriplets=divby9(intArr);

		System.out.println("The Triplets of numbers which are divisible by 9");
		for(int i=0;i<retTriplets.size();i+=3)
			System.out.println(retTriplets.get(i)+"    "+retTriplets.get(i+1)+"    "+retTriplets.get(i+2));
	}
}