How to find array triplets with sum of two elements equals other element in the same array

public class SumofNnumbers {

	public static void main(String[] args) {

		int [] numArray= {50, 108, 47, 61, 34, 184, 97, 71, 87};	
		int arrLen=numArray.length;
		System.out.println("The given array of numbers are");
		System.out.print("[");
		for (int i=0;i<arrLen;i++)
			System.out.print(numArray[i]+" ");
		System.out.println("]");
		System.out.println("Triplets -> Sum of any two numbers must be available in the array itself");
		System.out.println("FirstNum	SecondNum	SumNum");

		/* Nested for loop designed here to find sum of all possible pairs,
		 * and call the boolean function SrchSumInArr to check whether this sum
		 is available as one of the numbers in array itself. */

		for(int i=0;i<arrLen;i++)
			for (int j=i+1;j<arrLen;j++)
				if (SrchSumInArr(numArray[i]+numArray[j],numArray))
					System.out.println(numArray[i]+"		"+numArray[j]+"		"+(numArray[i]+numArray[j]));
	}

	private static boolean SrchSumInArr(int sumVal, int[] tmpArray) {

		// Search the calculated sum in the array, if not found return false
		boolean numFound=false;
		for(int i=0;i<tmpArray.length;i++)
			if(tmpArray[i]==sumVal)
				numFound=true;
		return numFound;
	}
}